A word consists of 9 letters; 5 consonants and 4 vowels.Three letters are choosen at random. What is the probability that more than one vowel will be selected ?

A 13/42

B 17/42

C 5/42

D 3/14

Correct Answer: Option B

3 letters can be choosen out of 9 letters in \(9C_3\) ways.

More than one vowels ( 2 vowels + 1 consonant or 3 vowels ) can be choosen in \((4C_2\times5C_1)+4C_3\) ways

Hence,required probability = \(\frac{\left(4C_2\times5C_1\right)+4C_3}{9C_3}\) = 17/42