Two cards are drawn from a pack of well shuffled cards. Find the probability that one is a club and other in King

A 1/52

B 1/26

C 1/13

D 1/2

Solution

Correct Answer: Option B

Let X be the event that cards are in a club which is not king and other is the king of club.
Let Y be the event that one is any club card and other is a non-club king.
Hence, required probability:
=P(A)+P(B)

= \(\left[\frac{12C_1\times1C_1}{52C_2}\right]+\left[\frac{13C_1\times3C_1}{52C_2}\right]\)

= \(\left[12\times\frac2{52\times51}\right]+\left[13\times3\times\frac2{52\times51}\right]\)

= \(\frac{24+78}{52\times51}\)

= \(\frac1{26}\)

Solution

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