There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?
Solution
Correct Answer: Option D
Total cases of checking in the hotels = 4 x 4 x 4 = 64 ways.
Cases when 3 men are checking in different hotels = 4×3×2 = 24 ways.
Required probability =24/64 = 3/8
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