Find the probability of selecting 2 woman when four persons are choosen at random from a group of 3 men, 2 woman and 4 children.
Correct Answer: Option C
Out of 9 persons,4 can be choosen in \(9C_4\) ways =126.
Favourable events for given condition = \(2C_2\times7C_2\) = 21.
So,required probability = 21/126 =1/6.
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