The probability that a bowler bowled a ball from a point will hit by the batsman is \(\frac14\). Three such balls are bowled simultaneously towards the batsman from that very point. What is the probability that the batsman will hit the ball ?
Solution
Correct Answer: Option A
Probability of not hitting the ball = 1- 1/4 = \(\frac34\)
Then, the probability that the batsman will hit the ball = \(1-(\frac34)^{3\;}=\frac{37}{64}\)
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