Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ?
Correct Answer: Option A
Let the present age of Pinky be x years
Then the age of Mary is x - 12 years
After 3 years,
Ratio of \(\frac{Mary}{Pinky}\;=\;\frac{\mathrm x\;-\;9}{\mathrm x\;+\;3}\;=\;\frac58\)
8x - 72 = 5x +15
=> 3x = 87
=> x = 29
=> Age of Pinky = 29 years
=> Age of Mary = 29 - 12 = 17 years
Present age of Sam = 29 + 17 = 46
Before 15 years Sam age = 46 - 15 = 31 years.
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