Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ?

A 31 years

B 37 years

C 46 years

D 29 years

Solution

Correct Answer: Option A

Let the present age of Pinky be x years

 

Then the age of Mary is x - 12 years

 

After 3 years,

 

Ratio of \(\frac{Mary}{Pinky}\;=\;\frac{\mathrm x\;-\;9}{\mathrm x\;+\;3}\;=\;\frac58\)

8x - 72 = 5x +15

 

=> 3x = 87

 

=> x = 29

 

=> Age of Pinky = 29 years

 

=> Age of Mary = 29 - 12 = 17 years

 

Present age of Sam = 29 + 17 = 46

 

Before 15 years Sam age = 46 - 15 = 31 years.

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