15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take if 3 women do as much as 2 men ?
Correct Answer: Option D
Solution: 3 women = 2 man 21 women = 14 men
15 man works 8 hours for = 21 days
1 " " 1 " " = 21 \( \times \) 8 \( \times \) 15 days
14 " " 6 " " = (21 \( \times \) 8 \( \times \) 15) / (14 \( \times \) 6) = 30 days
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