log₂ √6 + log₂ √(2/3) = কত?

A 0

B 2

C 1

D 3

Correct Answer: Option C

log₂ √6 + log₂ √(2/3)

= log₂ √3.2 + log₂ √2/√3 21/2

= log₂^√3 + log₂^√2 + log₂^√2 + log₂^√3

= log₂^√2 + log₂^√2 = 2 log₂^√2 = 2 log₂^{2^1/2} = 1/2 × 2 log₂2

= 1 × 1 = 1