If (x + 4)2 = 9 and (y + 3)2 = 25, then the minimum value of \(\frac{y}{x}\) is
Solution
Correct Answer: Option B
Solution:
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(x+4)2 = 9 => x + 4 = \( \pm \)3 x = -1 , -7 |
(y + 3)2 = 25 => y + 3 = \( \pm \)5 y = 2 , -8 |
\(\frac{y}{x}\) এর মানগুলো হলো \(\frac{2}{{ - 1}},\frac{{ - 8}}{{ - 1}},\frac{2}{{ - 7}},\frac{{ - 8}}{{ - 7}}\) এদের মধ্যে \(\frac{y}{x}\) এর সর্বনিম্ন মান \(\frac{2}{{ - 1}}\) = -2 |
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