1/3 + 1/32 + 1/33...... অনন্ত ধারার মান কত হবে?
Solution
Correct Answer: Option B
এখানে,
১ম পদ a = 1/3
সাধারণ অনুপাত r = (1/32) ÷ (1/3)
= (1/9) × (3/1)
= 1/3
অসীমতক সমষ্টি = a/(1 - r)
= (1/3)/{1 - (1/3)}
= (1/3)/{(3 - 1)/3}
= (1/3)/(2/3)
= (1/3) × (3/2)
= 1/2
১ম পদ a = 1/3
সাধারণ অনুপাত r = (1/32) ÷ (1/3)
= (1/9) × (3/1)
= 1/3
অসীমতক সমষ্টি = a/(1 - r)
= (1/3)/{1 - (1/3)}
= (1/3)/{(3 - 1)/3}
= (1/3)/(2/3)
= (1/3) × (3/2)
= 1/2
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