log2√6 + log2√(2/3) = ?

B 1

C 3

D 4

Solution

Correct Answer: Option B

log2√6 + log2√(2/3)

= log2√(2 × 3) + log2√2 - log2√3

= log2√2 + log2√3 + log2√2 - log2√3

= 2 log2√2
= log2(√2)2
= log22
= 1

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