If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

A 55/601

B 601/55

C 11/120

D 120/11

Correct Answer: Option C

Let the numbers be a and b.

Then, a + b = 55 and ab = 5 x 120 = 600.

The required sum = 1/a+1/b

= (a + b)/ab= 55/600 = 11/120