How many \({1 \over 9}\) are there in \(33{1 \over 3}\) ?
Correct Answer: Option B
\(33{1 \over 3} = 33 + {1 \over 3} = {{100} \over 3}\)
∴ Number of \({1 \over 9}\) in \({{100} \over 3} = {{{{100} \over 3}} \over {{1 \over 9}}} = {{100 \times 9} \over 3} = 300\)
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