In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer I. 2x2 + 5x + 2 = 0 II. 4y2 = 1

In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer

I. 2x² + 5x + 2 = 0

II. 4y² = 1

A x < y

B x > y

C x ≤ y

D x ≥ y

E x = y

Solution

Correct Answer: Option C

We will separately solve both equations.

Equation 1:

2x² + 5x + 2 = 0

⇒ 2x² + 4x + x + 2 = 0

⇒ 2x (x + 2) + 1 (x + 2) = 0

⇒ (x + 2) × (2x + 1) = 0

⇒ x = -2 or, x = -½

Equation 2:

4y² = 1

⇒ 4y² – 1 = 0

⇒ (2y)² – 1 =0

⇒ (2y – 1) × (2y + 1) = 0

⇒ y = ½ or, y = -½

x & y both have one common value. That is -½.

So we can say x = y

Another value of y (y = ½) is greater than another value of x (x = -2)

So we can say y > x

Combining both y ≥ x

Solution

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