If the number 97215k6 is completely divisible by 11, then the smallest whole number in place of ‘K’ would be:
Correct Answer: Option B
We know that:
A number is divisible by 11 if difference between the sum of its digits at odd places and the sum of its digits at even places is either 0 or a number divisible by 11.
Given number = 97215k6
So, (6+5+2+9) - (k + 1 + 7) = (14 - k), which must be divisible by 11
∴ K = 3
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