Find the least number which when divided by 48, 60, 72, 108, and 110, leaves the remainders 38, 50, 62, 98, and 100, respectively.
Correct Answer: Option E
For the least number which when divided by 48, 60, 72, 108, and 110, leaves the remainders 38, 50, 62, 98, and 100, respectively
We subtract the remainder from the values respectively:
(48 – 38) = (60 - 50) = (72 - 62) = (108 - 98) = (110 - 100) = 10 in every case
LCM of 48, 60, 72, 108, and 110 is 23760
So, required number = 23760 – 10 = 23750
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