A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is
Correct Answer: Option C
let ABCD be the given parallelogram
area of parallelogram ABCD = 2 x (area of triangle ABC)
now a = 30m, b = 14m and c = 40m
s=1/2 x (30+14+40) = 42
Area of triangle ABC = \(\sqrt{\left[s\left(s-a\right)\left(s-b\right)\left(s-c\right)\right]}\)
= \(\sqrt{\left[42\left(12\right)\left(28\right)\left(2\right)\right]}\)
= 168sq m
area of parallelogram ABCD = 2 x 168 = 336 sq m
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