The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475 find the lengths of the parallel sides.
Correct Answer: Option A
Let the two parallel sides of the trapezium be a cm and b cm.
Then, a - b = 4
And, \(\frac12\times\left(a+b\right)\times19=475=>\left(a+b\right)=50\)
Solving (i) and (ii), we get: a = 27, b = 23.
So, the two parallel sides are 27 cm and 23 cm.
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