The perimeters of two squares are 40cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.
Solution
Correct Answer: Option B
side of first square = 40/4 =10cm
side of second square = 32/4 = 8cm
area of third squre = 10² - 8² = 36 sq cm
side of third square = \(\sqrt{36}\)
= 6 cm
required perimeter = 6*4 = 24cm
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