The product of two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is 

A 101

B 107

C 111

D 185

Solution

Correct Answer: Option C

Let the numbers be 37a and 37b. 

Then , 37a x 37b =4107  => ab = 3.

Now co-primes with product 3 are (1,3)

 So, the required numbers are (37 x 1, 37 x 3) i.e, (37,111).

 Therefore, Greater number = 111.

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