A heap of coconuts is divided into groups of 2, 3 and 5 and each time one coconut is left over. The least number of Coconuts in the heap is  ?

A 63

B 31

C 16

D 27

Solution

Correct Answer: Option B

To get the least number of coconuts :
LCM = 30 => 30 + 1 = 31

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