If two letters are taken at random from the word HOME, what is the probability that none of the letters would be vowels?

A 1/6

B 1/2

C 1/3

D 1/4

Correct Answer: Option A

P(first letter is not vowel) = \(\frac24\)

P(second letter is not vowel) = \(\frac13\)

So, probability that none of letters would be vowels is = \(\frac24\times\frac13=\frac16\)