A bag contains 50 tickets numbered 1,2,3,4......50 of which five are drawn at random and arranged in ascending order of magnitude.Find the probability that third drawn ticket is equal to 30.

A 551/15134

B 1/2

C 552/15379

D 1/9

Correct Answer: Option A

Total number of elementary events = ⁵⁰c₅

Given,third ticket =30

=> first and second should come from tickets numbered 1 to 29 = ²⁹c₂ways and remaining two in ²⁰c₂ways.

Therfore,favourable number of events = \(29C_2\times20C_2\)

Hence,required probability = \(\frac{29C_2\times20C_2}{50C_5}\) = 551 / 15134