A box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains exactly one defective bulb

A 5/12

B 7/12

C 3/14

D 1/12

Correct Answer: Option A

Total number of elementary events = \(10C_5\)

Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is \(3C_1\times7C_4\)

So,required probability = \(\frac{3C_1\times7C_4}{10C_5}\) = 5/12.