If a box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains no defective bulbs.

A 5/12

B 7/12

C 3/14

D 1/12

Correct Answer: Option D

Total number of elementary events = \(10C_5\)

Number of ways of selecting no defective bulbs i.e., 5 non-defective bulbs out of 7 is \(7C_5\)

So,required probability = \(\frac{7C_5}{10C_5}\) = 1/12.