In a simultaneous throw of two dice, what is the probability of getting a doublet ?

A 1/6

B 1/3

C 4/7

D 4/5

Correct Answer: Option A

In a simultaneous throw of two dice, n(S) = 6 x 6 = 36

Let E = event of getting a doublet = { (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}

\(P(E)=\frac{n(E)}{n(S)}=\frac6{36}=\frac16\)