One card is drawn from a pack of 52 cards , each of the 52 cards being equally likely to be drawn. Find the probability that the card  drawn is neither a spade nor a king.

A 0

B 9/13

C 1/2

D 4/13

Solution

Correct Answer: Option B

There are 13 spades ( including one king). Besides there are 3 more kings in remaining 3 suits

 

Thus   n(E) = 13 + 3 = 16

Hence \(n\left(\overline E\right)=52-16=36\)

Therefore, \(P\left(\overline E\right)=\frac{36}{52}=\frac9{13}\)

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