One card is drawn from a pack of 52 cards , each of the 52 cards being equally likely to be drawn. Find the probability that the card drawn is neither a spade nor a king.
Correct Answer: Option B
There are 13 spades ( including one king). Besides there are 3 more kings in remaining 3 suits
Thus n(E) = 13 + 3 = 16
Hence \(n\left(\overline E\right)=52-16=36\)
Therefore, \(P\left(\overline E\right)=\frac{36}{52}=\frac9{13}\)
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