Three fair coins are tossed simultaneously. Find the probability of getting more heads than the number of tails

A 2

B 7/8

C 5/8

D 1/2

Correct Answer: Option D

S = { HHH, HHT, HTH, HTT, THH, THT, TTH, TTT }

=> n(S) = 8

E = { HHH, HHT, HTH, THH }

=> n(E) = 4

P(E) = 4/8 = 1/2