Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ?
Solution
Correct Answer: Option B
Given sum of present ages of A, B, C & D
A + B + C + D = 176
and also given that,
(A-4) : (B-4) : (C-4) : (D-4) = 11 : 9 : 6 : 14
Let the ratio = x
=> A-4 + B-4 + C-4 + D-4 = 11x + 9x + 6x + 14x
=> (A + B + C + D ) - 16 = 40x
=> 176 - 16 = 40x
=> x = 4
=> A = 44 + 4 = 48
=> B = 40
=> C = 28
=> D = 60
Therefore, from the above conclusions
D is eldest with 60 years and C is youngest with 28 years of ages.
Practice More Questions on Our App!
Download our app for free and access thousands of MCQ questions with detailed solutions