tanθ = 1/2 হলে sin2θ এর মান কত?
সমাধান
সঠিক উত্তর: Option D
tanθ = 1/2
এখন, sin2θ = 2tanθ/(1+tan2θ) [এটি সূত্র]
= 2×(1/2) / 1+(1/2)2
= 1/ (1 + 1/4)
= 1/(5/4)
= 1 × (5/4)
= 4/5
এখন, sin2θ = 2tanθ/(1+tan2θ) [এটি সূত্র]
= 2×(1/2) / 1+(1/2)2
= 1/ (1 + 1/4)
= 1/(5/4)
= 1 × (5/4)
= 4/5