A 0
B 1
C 3abc
D abc
Correct Answer: Option C
a+b+c = 0
=> a+b = - c
=> (a+b)3 = -c3
=> a3+ b3 + 3ab(a+b) = -c3
=> a3+ b3 + 3ab(-c) = -c3
=> a3+ b3 -3abc = - c3
=> a3+ b3 + c3 =3abc
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