Correct Answer: Option B
Marking (/) those which are are divisible by 3 by not by 9 and the others by (X), by taking the sum of digits, we get:s
2133 –> 9 (X)
2343 –> 12 (/)
3474 –> 18 (X)
4131 –> 9 (X)
5286 –> 21 (/)
5340 –> 12 (/)
6336 –> 18 (X)
7347 –> 21 (/)
8115 –> 15 (/)
9276 –> 24 (/)
Required number of numbers = 6.
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