(a-b)/ab+(b-c)/bc+(c-a)/ca=?

B 1

C 1/2

D 1/abc

Solution

Correct Answer: Option A

(a-b)/ab + (b-c)/bc + (c-a)/ca

= (c - a) /ac + (a - b) /ab + (b - c) /bc

= (c/ac - a/ac) + (a/ab - b/ab) + (b/bc - c /bc)

= (1/c - 1/a) + (1/ a - 1/b) + (1/b - 1/c)

= 0

Solution

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