Correct Answer: Option B
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres
So, (27x + 17y)/(x+ y) = 23
=> 27x + 17y = 23x + 23y
=> 4x = 6y
=> x/y = 3/2.
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