Correct Answer: Option C
Let, AB be the lighthouse and C and D be the positions of the ships.
Then, AB = 100 m, ÐACB = 30º and ÐADB = 45º.
AB/ AC= tan 30º = 1 /√3
=>AC = AB ×√3 = 100√3 m.
=> AB/AD= tan 45º = 1
=>AD=AB=100m.
So, CD = (AC + AD) = (100√3 + 100) m
= 100(√3 + 1)
= (100 × 2.73) m
= 273 m.
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