Set X contains 10 consecutive integers. If the sum of the 5 smallest members of set X is 265, what is the average of the 5 largest members of Set X?

Set X contains 10 consecutive integers. If the sum of the 5 smallest members of set X is 265, what is the average of the 5 largest members of Set X?

A 58

B 59

C 60

D 57

Solution

Correct Answer: Option A

x+x+x+x+x+1+2+3+4+5 = 265

or, 5x + 15 = 265

or, 5x = 265 - 15 = 250

or, x = 50

The largest 5 member of the set is,

50+6 = 56

50+7 =57

50+8 = 58

50+9= 59

50+10= 60

Then,

Average = (56+57+58+59+60) / 5

= 290/5

= 58