if \({1 \over {10}}:{1 \over a} = {1 \over a}:{1 \over 1},\) ,110:1a=1a:11,then value of a is
Correct Answer: Option B
Given that,
\(\eqalign{ & {{{1 \over {10}}} \over {{1 \over a}}} = {{{1 \over a}} \over 1} \cr & \Rightarrow {a \over {10}} = {1 \over a} \cr & \Rightarrow {a^2} = 10 \cr & \Rightarrow a = \sqrt {10} \cr}\)
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