In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark correct answer. I. \(\frac{{{{\left( 2 \right)}^5} + {{\left( {11} \right)}^3}}}{6} = {x^3}\) II. 4y3 =

In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark correct answer.

I. \(\frac{{{{\left( 2 \right)}^5} + {{\left( {11} \right)}^3}}}{6} = {x^3}\)

II. 4y³ = - (589 ÷ 4) + 5y³

A x > y

B x ≥ y

C x < y

D x ≤ y

E x = y or the relation cannot be determined

Solution

Correct Answer: Option A

We will solve both the equations separately.

Equation I:

\(\frac{{{{\left( 2 \right)}^5} + {{\left( {11} \right)}^3}}}{6} = {x^3}\)

\(\Rightarrow \frac{{32 + 1331}}{6} = {x^3}\)

⇒ x³ = 1363/6 = 227.167

Equation II:

4y³ = - (589 ÷ 4) + 5y³

⇒ 4y³ = - (589/4) + 5y³

⇒ y³ = 589/4 = 147.25

Comparing the values of x and y we get,

x > y

Solution

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