3/8 of all applicants for a job are male. 3/4 of all applicants are rejected in the first round including 2/3 of all male applicants. What fraction of applicants remaining after the first round are male?
Solution
Correct Answer: Option A
মনে করি, মোট = x
∴ Male = 3x/8
তাহলে, Female = (x-3x)/8 = 5x/8
rejected applicants = (3/4)× x
=3x/4
rejected male applicants = (2/3) × (3x/8)
=x/4
rejected female applicants = (3x/4) - (x/4)
=(3x-x)/4
=2x/4
=x/2
after first round remaining male = (3x/8) - (x/4)
=x/8
after first round remaining female = 5x/8-x/2
=x/8
Total = (x/8)+(x/8) = 2x/8 = x/4
male remains from total remaining is = (x/8)/(x/4)
= x/8 × 4/x
= 1/2
∴ Male = 3x/8
তাহলে, Female = (x-3x)/8 = 5x/8
rejected applicants = (3/4)× x
=3x/4
rejected male applicants = (2/3) × (3x/8)
=x/4
rejected female applicants = (3x/4) - (x/4)
=(3x-x)/4
=2x/4
=x/2
after first round remaining male = (3x/8) - (x/4)
=x/8
after first round remaining female = 5x/8-x/2
=x/8
Total = (x/8)+(x/8) = 2x/8 = x/4
male remains from total remaining is = (x/8)/(x/4)
= x/8 × 4/x
= 1/2
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