In a simultaneous throw of two dice, what is the probability of getting a total of (7)?
Correct Answer: Option C
We know that in a simultaneous throw of two dice -
Number of sample space n(s) = 6×6=36
Let E = event of getting a total of 7
= {(1,6) (2,5) (3,4) (4,3) (5,2) (6,1)}
Therefore numbers of event n(E) = 6
∴probability of getting a total of 7
\(P\left( E \right) = \frac{{n\left( E \right)}}{{n\left( S \right)}} = \frac{6}{{36}} = \frac{1}{6}\)
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