The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?
Correct Answer: Option D
Let original length = x and original breadth = y.
Original area = xy.
New length = x/2 and New breadth=3y
New area = \(\frac32xy\)
Therefore, Increase in area = New area-original area
= \(\frac32xy-xy=\frac12xy\)
Therefore, Increase % = \(\frac{increase\;in\;area\;}{original\;area}\ast100=\left(\frac{\displaystyle\frac12xy}{xy}\right)\ast100=50\)%
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