In measuring the sides of a rectangle, one side is taken 5% in excess and the other 4% in deficit. Find the error percent in the area, calculate from the those measurements.
Correct Answer: Option B
let x and y be the sides of the rectangle then
correct area = \(\frac{105}{100}x\times\frac{96}{100}y\)
Error% = \(\frac{504}{500}xy-xy=\frac4{500}xy\) %
\(\frac4{500}xy\times\frac1{xy}\times100=\frac45=0.8\)
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