A cricketer has a certain average for 10 innings, In the eleventh inning, he scored 108 runs, thereby increasing his average by 6 runs. His new average is :

A 44 runs

B 46 runs

C 48 runs

D 49 runs

Correct Answer: Option C

Let average for 10 innings be x. Then,

(10x + 108) \(\div\) 11 = x + 6 => 11x + 66 = 10x + 108 => x = 42.

New average = (x + 6) = 48 runs.