logk(an/bn) + logk(bn/cn) + logk(cn/an) = ?

A ab

B logka/b

C logkb/c

D 0

Solution

Correct Answer: Option D

 logk(an/bn) + logk(bn/cn) + logk(cn/an

=> logk (a/b)^n +  logk (b/c)^n +  logk (c/a)^n 

=> n  logk a/b + n  logk b/c + n  logk c/a 

=> n (  logk a/b +  logk b/c +  logk c/a) 

=> n { logk (a/b×b/c×c/a)} 

=> n  logk

=> n×0       [  logk 1 = o ] 

 => 0 

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