(লিখিত প্রশ্ন) A shopkeeper buys 100 mangoes at Tk. 12 each. He sells 60 mangoes at Tk. 17.40 each and x mangoes at Tk. 11.31 each. The shopkeeper makes a profit of at least 10%. Find the least possible value of x.
Solution
Correct Answer: Option B
প্রশ্নে বলা হচ্ছে, একজন দোকানদার 12 টাকা দরে 100 টি আম ক্রয় করলো। সে 60 টি আম 17.40 টাকা দরে বিক্রয় করলো এবং x টি আম 11.31 টাকা দরে বিক্রয় করলো। দোকানদার কমপক্ষে 10% মুনাফা করলে x এর সম্ভাব্য সর্বনিম্ন মান কত?
The cost of 100 mangoes is Tk. (100 x 12)= Tk. 1,200
Selling price of 60 mangoes is Tk. (17.40 x 60) Tk. 1,044
And selling price of x mangoes is Tk. (x x 11.31)= Tk. 11.31x
As, the shopkeeper made at least 10% profit, so his total selling price would be
Tk. (1,200 + 1,200 × 10%)
= Tk.1,200 + {(1,200 × 10)/100}
= Tk. (1,200 + 120)
= Tk. 1,320
প্রশ্নমতে, 1,044 + 11.31x ≥ 1,320
⇒ 11.31x ≥ 1,320 - 1,044
⇒ 11.31x ≥ 276
⇒ x ≥ (276/11.31)
∴ x ≥ 24.403
As the number of mangoes can not be the decimal number. So the least possible value of mangoes will be 25.
The cost of 100 mangoes is Tk. (100 x 12)= Tk. 1,200
Selling price of 60 mangoes is Tk. (17.40 x 60) Tk. 1,044
And selling price of x mangoes is Tk. (x x 11.31)= Tk. 11.31x
As, the shopkeeper made at least 10% profit, so his total selling price would be
Tk. (1,200 + 1,200 × 10%)
= Tk.1,200 + {(1,200 × 10)/100}
= Tk. (1,200 + 120)
= Tk. 1,320
প্রশ্নমতে, 1,044 + 11.31x ≥ 1,320
⇒ 11.31x ≥ 1,320 - 1,044
⇒ 11.31x ≥ 276
⇒ x ≥ (276/11.31)
∴ x ≥ 24.403
As the number of mangoes can not be the decimal number. So the least possible value of mangoes will be 25.
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