sin2θ + cos2θ = ?

A 1/√2

B √3/2

C 1/2

D 1

Solution

Correct Answer: Option D

sin2θ + cos2θ
= (লম্ব/অতিভুজ) + (ভূমি/অতিভুজ)
= (লম্ব + ভূমি)/অতিভুজ
= অতিভুজ/অতিভুজ 
= ১

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