x এর মান কত হলে {3/(x-2)} + {5/(x-6)} = 8/(x+3) হবে?

A 1

B 2

C 3

D 4

Solution

Correct Answer: Option C

{3/(x-2)} + {5/(x-6)} = 8/(x+3)
(x-2)(x-6)(x+3) দিয়ে উভয় পক্ষ গুণ করি:
3(x-6)(x+3) + 5(x-2)(x+3) = 8(x-2)(x-6)
8x²-4x-84 = 8x²-64x+96
60x = 180
x = 3

∴ x = 3

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