Correct Answer: Option E
Explanation:
C I = P[(1+ r/100)n -1]
S I = P r n /100
Given, CI is compounded every six months,
in this case r = 30/2 =15% and n =3
Let ‘P’ be the required sum,
Then, P [(1+ 15/100)³ -1] – P × 30 × 1.5/100
= Tk.5670
i.e. P [ ( 1.15 × 1.15 × 1.15) – 1] – 0.45P = 5670
P( 1.520875 – 1) – 0.45P = 5670
P ( 0.520875 – 0.45) = 5670
P = 5670/0.70875
= TK.80000.
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