mn√(xm/xn) × nl√(xn/xl) × lm√(xl/xm) = ?
Solution
Correct Answer: Option C
mn√(xm/xn) × nl√(xn/xl) × lm√(xl/xm)
= (xm-n)1/mn × (xn-l)1/nl × (xl-m)1/lm
= xm-n/mn × xn-l/nl × xl-m/lm
= xm-n/mn + n-l/nl + l-m/lm
= x{l(m-n) + m(n-l) + n(l-m)}/mnl
= x(lm - nl + mn - lm + nl - mn)/mnl
= x0/mnl
= x0
= 1