Given that 1048 = x, 1070 = y and xz = y2, then the value of z is close to:

Given that 10⁴⁸ = x, 10⁷⁰ = y and x^z = y², then the value of z is close to:

A 1.45

B 1.88

C 2.9

D 3.7

Correct Answer: Option C

xz = y2

=> 10(0.48z) = 10(2 x 0.70) = 101.40

=> 0.48z = 1.40

=> z = 140/48 = 35/12 = 2.9 (approx.)